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3sum problem (finding triplets) in better than o (n^2) asked 13 years, 5 months ago modified 2 years, 7 months ago viewed 6k times Given an array of n integers nums and a target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condi. This looks like the standard approach to solving 3sum in quadratic time
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However, i disagree with the other answers concerning space complexity and believe it is quadratic as there can be quadratically many distinct triples summing to 0. A problem called 3sum smaller on leetcode asks I'm studying the 3 sum to implement it on my own, and came across the following implementation with the rules
Given an array s of n integers, are there elements a, b, c in s such that a + b + c =.
Solving the leetcode 3sum problem in python asked 7 years ago modified 7 years ago viewed 2k times Given an array a of integers, find any 3 of them that sum to any given t I saw this on some online post, which claims it has a o(nlogn) solution For 2 numbers, i know hashtable could help for o.
4 i am working on the 3sum problem (taken from leetcode), which takes a list as input and finds all unique triplets in the lists such that a+b+c=0 You'll need to complete a few actions and gain 15 reputation points before being able to upvote Upvoting indicates when questions and answers are useful What's reputation and how do i get it
Instead, you can save this post to reference later.
How do i return all possible triplets in the 3sum problem Asked 3 years, 5 months ago modified 2 years, 6 months ago viewed 2k times The naïve approach is o (n³) But you can easily improve on that bound by first indexing the numbers and then computing all the sums of pairs, storing them in a hash table and then lookup if the negative of the sums exists and test if its components have not already been used in.
