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11111111111111111 is a decimal number literal for a number that is too large for javascript to encode precisely Why is it doing this? Parseint(, 2) will stop at the first character that isn't 1 or 0, so it stops parsing once the precision degrades.
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I am facing weird issued But when i am providing '11111111111111111' to a textbox, parseint is converting it into 11111111111111112 instead of 11111111111111111 Parsefloat (11111111111111111) converts it to 11111111111111112
I noticed that it works fine till length is 16 but rounds off higher when input length is > 16.
This isn't a good way to do this & would result in wildly inaccurate answers if the number had many digits to the right of the decimal, and its conversion to a string contained exponential notation Try the above code with the following division equation Why does sys.getrefcount() return 3 for every large number or simple string?does that mean that 3 objects reside somewhere in the program?also,why doesn't setting x=(very large number) increase t. 1111111111111 + 11111111111111 + 111111111111111 + 1111111111111111 + 11111111111111111 + 1111111111111111 11 + 1111111111111111111 + 11111111111111111111 + 111111111111111111111 + 1111111111111111111111 + 11111111111111111111111 +
For example, 77777777777777777/7 returns the value 11111111111111112 (instead of 11111111111111111 as it should) If i go to even larger numbers the problem becomes more pronounced (i.e Deviates even more from the correct value). While writing a program i came across a case where a large integer with a decimal point at the end is printed with different values when casted with different data types
In this code from wtfjs, apparently something goes wrong
// alerts 111111111111111110000 i did some tests and found that 11111111111111111 === 11111111111111112 What happens when you try 11111111111111111/2, without the int What happens if you try float(11111111111111111)? I want to add two numbers in javascript
