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3sum problem (finding triplets) in better than o (n^2) asked 13 years, 5 months ago modified 2 years, 7 months ago viewed 6k times It's better we should go for ksum solution. This looks like the standard approach to solving 3sum in quadratic time
3SUM BEAR
However, i disagree with the other answers concerning space complexity and believe it is quadratic as there can be quadratically many distinct triples summing to 0. But what about the 6sum, 7sum and so on I'm studying the 3 sum to implement it on my own, and came across the following implementation with the rules
Given an array s of n integers, are there elements a, b, c in s such that a + b + c =.
Given an array a of integers, find any 3 of them that sum to any given t I saw this on some online post, which claims it has a o(nlogn) solution For 2 numbers, i know hashtable could help for o. Solving the leetcode 3sum problem in python asked 7 years ago modified 7 years ago viewed 2k times
4 i am working on the 3sum problem (taken from leetcode), which takes a list as input and finds all unique triplets in the lists such that a+b+c=0 The naïve approach is o (n³) But you can easily improve on that bound by first indexing the numbers and then computing all the sums of pairs, storing them in a hash table and then lookup if the negative of the sums exists and test if its components have not already been used in. I tried solving the 3sum problem on leetcode in python 3 but it shows that the time limit has exceeded for my solution
3sum problem is as follows
Given array nums of n integers, are there element. How do i return all possible triplets in the 3sum problem Asked 3 years, 5 months ago modified 2 years, 6 months ago viewed 2k times 4sum and 3sum are very similar
The difference is that we are looking for unique quadruplets instead of triplets Following a similar logic, we can implement 5sum by wrapping 4sum in another loop
